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The day-of-week calculation used the raw year value without adjusting for TM_YEAR_BASE, so it was off by one for 300 years out of every 400; it just happened to be correct for 1901 through 2000. It also used a loop where a simple addition would have sufficed. While here, simplify our version of Gauss's algorithm, and document that we assume the Gregorian calendar. MFC after: 1 week PR: 282916 Reviewed by: imp, allanjude, philip Differential Revision: https://reviews.freebsd.org/D47977
50 lines
1,008 B
C
50 lines
1,008 B
C
/*-
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* Copyright (c) 2024 Dag-Erling Smørgrav
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*
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* SPDX-License-Identifier: BSD-2-Clause
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*/
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#include <time.h>
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#include <atf-c.h>
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ATF_TC_WITHOUT_HEAD(dayofweek);
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ATF_TC_BODY(dayofweek, tc)
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{
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static const struct {
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const char *str;
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int wday;
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} cases[] = {
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{ "1582-12-20", 1 },
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{ "1700-03-01", 1 },
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{ "1752-09-14", 4 },
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{ "1800-12-31", 3 },
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{ "1801-01-01", 4 },
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{ "1900-12-31", 1 },
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{ "1901-01-01", 2 },
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{ "2000-12-31", 0 },
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{ "2001-01-01", 1 },
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{ "2100-12-31", 5 },
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{ "2101-01-01", 6 },
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{ "2200-12-31", 3 },
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{ "2201-01-01", 4 },
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{ },
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};
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struct tm tm;
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for (unsigned int i = 0; cases[i].str != NULL; i++) {
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if (strptime(cases[i].str, "%Y-%m-%d", &tm) == NULL) {
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atf_tc_fail_nonfatal("failed to parse %s",
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cases[i].str);
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} else if (tm.tm_wday != cases[i].wday) {
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atf_tc_fail_nonfatal("expected %d for %s, got %d",
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cases[i].wday, cases[i].str, tm.tm_wday);
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}
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}
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}
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ATF_TP_ADD_TCS(tp)
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{
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ATF_TP_ADD_TC(tp, dayofweek);
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return (atf_no_error());
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}
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